A capacitor of capacity `C_(0)` is conneted to a battery of emf`V_(0)` When steady state is attained a dielectric slab of dielectric constant K is slowly introduced in the capacitor to fill the capacitor completely. Mark the correct statement(s), in final stady state.

Options

A. Magnitude of induced charge on the each surface of slab is `C_(0)V_(0)(K-1)`
B. Electric force due to induced charges on any plate is zero.
C. Force of attraction between plates of capacitor is `(K(C_(0)V_(0))^(2))/(2in_(0)A)`
D. Field due to induced charges in dielectric slab is `((K-1)C_(0)V_(0))/(in_(0)A)`

Answer

A, B, D

Explanation

Charged induced on the surface of dielectric slab
`=kC_(0)V_(0)(1-1/k)=(k-1)C_(0)V_(0)`
`(B)-(k-1)C_(0)V_(0)+(k-1)C_(0)V_(0)`


Resultant field is zero due to charge on both the surfaces.
(C) Force of attraction `=((kC_(0)V_(0))/(2 in_(0)A) (kC_(0)V_(0)) = ((k^(2)C_(0)V_(0))/(2 in_(0)A)`
(D) `((k-1)C_(0)V_(0))/(in_(0)A)`