A block is placed on a rough horizontal surface having coefficient of friction mu. A variable force `F=kt,(0 lt t lt (mg)/(ksintheta)` acts on it at an angle `theta` to

Answer

[(A)Q(B)S(C)P(D)R]

Explanation

(1)`N-mg-Fsintheta-mg-(ksintheta)t` :.Graph(Q)for Normal reaction
`(2) f_(max)=muN=mumg-(muksintheta)t`
`f=Fcostheta=(kcostheta)t`
for `t gt (mumg)/(k(costheta+usintheta))`
`f=mumg-(muksintheta)t`
Hence graph(S) for friction (3)`a=(F-f)/m`
`a=0 till F ltf_(max)`
`a=k(costheta+mumgsintheta)t-mug for F gt f_(max)`
Hence, graph (P) for acceleration
(4)`v=0 till F ltf_(max)`
`v=inta dt =(kcostheta+mumgsintheta)t^(2)/2-mug t forF ltf_(max)`
Hence graph (R) for velocity