A copper rod (initially at room temperature `20^(@)C`) of non-uniform cross section is placed between a steam chamber at `100^(@)C` and ice-water chamber at `0^(@)C`. `A` and `B` are cross sections are as shown in figure. Then match the statements in column -I with results in columns-II using comparing only between cross section `A` and `B`. (The mathematical expressions in column-I have usual meaning in heat transfer).

`{:(,"Column-I",,"Column-II"),((A),"initially rate of heat flow" ((dQ)/(dt))"will be ",(p),"Maximum at section" A),((B),"At steady state rate of heat flow" ((dQ)/(dt)) "will be ",(q),"Maximum at section" B),((C),"At steady state temperature gradient" |((dT)/(dx))| "will be " ,(r),"Minimum at section B"), ((D), "At steady state rate of change of temperature"((dT)/(dt)) " at a certain point will be",(s),"Same for all section"):}`

Explanation

(A) `L=mvr = m(sqrt(GM)/r)r`
`L prop sqrt(r)`
So angular momentum increases and becomes sqrt(2) times
(B)
`A=4piR^(2)-2xx2piR^(2)(1-costheta)=4piR^(2)costheta`
So area covered by satellite increases
(C) `U=-(GMm)/r`
So, when r is doubled PE becomes half and increases
(D) `KE=(GMm)r` So, KE decrease and becomes half