An extended object is moving in front of concave mirror as shown in figure On L.H.S velocity of object and position is given On R.H.S some properties of image and its velocity is given Consider velocity along x-axis only

`{:(,"Object",,"Image"),("(A)","+ve velocity and object is between focus and centre of curvature",,"(P)+ve velocity"),("(B)","-ve velocity and object is between focus and pole",,"(Q)-ve velocity"),("(C)","-ve velocity and object is beyond centre of curvature",,"(R)size of image is increasing"),("(D)","-ve velocity and object is virtual",,"(S)size of image is decreasing"):}`

Answer

[(A)QR;(B)PR;(C)PS;(D)PR]

Explanation

`v_(1)=(-v^(2))/u^(2)v_(0)`
(A) `if v_(0)=(+) Rightarrow v_(I)=(-) ve`
`|(h_(2)/h_(1))|=v/u as |u|` decreases Rightarrow `|v| increases Rightarrow` magnification increases
(B) as object goes from `P rightarrow f` image goes from `P rightarrow +infty`
`|v| uparrow |u| downarrow Rightarrow m^(2) uparrow`
(C) Object gas from `C rightarrow -infty` image goes from `C rightarrow focus`
`|u| uparrow |v| downarrow Rightarrow m^(2) downarrow`
(D) Object goes from `+infty rightarrow P` image goes from `-f rightarrow P`
`|v|downarrow |u| downarrow` v is decreases with a greater rate Rightarrow `m^(2) downarrow`