Q is energy released in the decay m_(x) is atomic mass of parent nucleus m_(y) is atomic mass of daughter nucleus and m_(e) is mass of elctron then match the following:
`{:(,"Column-I",,"Column-II"),("(A)","k capture",,(P) Q=(m_(x)-m_(y))c^(2)),("(B)",beta^(-) decay,,(Q)Q=(m_(x)-m_(y)-m_(c))c^(2)),("(C)",beta^(+) decay,,(R)Q=(m_(x)-m_(y)-2m_(e))c^(2)),(,,,(S)Q=(m_(x)-m_(y)+2m_(e))c^(2)),(,,,):}`

Answer

[(A)P(B)P(C)R]

Explanation

`Q= Delta mc^(2)`