Figure shows a block placed on a bracket. Bracket is placed on a smooth floor, it is pulled by a force F=6N horizontally Block is projected with velocity v_(0) relative to bracket as shown in figure. Find time in second after which it stops relative to bracket. Horizontal surface of bracket is smooth while vertical surface is rough (Given `m=1 kg M=5 kg v_(0)=5 m //s mu =0.5)` (Round off nearest integer)

Answer

`0010`

Explanation

`a_(x)=6/(1+5)=1 ms^(-2)`
`N=1xx1=1N`
`f_(r)=muN=1/2`
`a=(fr)/m=1/2`
`0=v_(0)-1/2xxt`
`t=10` sec