Two beads connected by a light inextensible string are placed over fixed vertical rings as shown in figure If mass of each bead is 100 gms and all surfaces are frictionless if the tension (T) in the string just after the beads are released from the shown position, then find `100T^(2) (in N^(2))`

Answer

`50`

Explanation

`N_(1)=T/sqrt(2)+mg T/sqrt(2)=ma` .....(1)
`T/sqrt(2)=N_(2) mg-T/sqrt(2)=ma` ....(2)
:.`mg-T/sqrt(2)=T/sqrt(2)Rightarrow mg=Tsqrt(2):.T=mg/sqrt(2)=((10^(-1))(10))/sqrt(2)=1/sqrt(2)N`
`:.100T^(2)=100(1/2)=50]`