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A spherical planet has uniform density p...

A spherical planet has uniform density `pi/2xx10^(4)kg//m^(3)`. Find out the minimum period for a satellite in a circular orbit around it in seconds (Use `G=20/3xx10^(-11) (N-m^(2))/(kg^(2))`).

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Verified by Experts

The correct Answer is:
`3000sec`

`T=(2piR)/V=2pi sqrt(R^(3))/(GM)=sqrt(3pi)/(GP)=3xx10^(3) sec=3000sec`
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