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Two particles of mass 'm' and 3 m are initially at rest an infinite distance apart. Both the particles start moving due to gravitational attraction. At any instant their relative velocity of approach is `sqrt((ne Gm)/d` where 'd' is their separation at that instant. Find ne.

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Verified by Experts

The correct Answer is:
`0008`
`(-GMxx3M)/d+1/2muV_(rel)^(2)`
`(+3GM^(2))/d=1/2xx(3M^(2))/(4M)xxV_(rel)^(2)`
`Rightarrow V_(rel)^(2)=(8GM)/d`
`V_(rel)=sqrt((8GM)/d Rightarrow ne=8`
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