Water kept in a porcus pot evaporates through the walls of pot. Rate of evaporation is proportional to volume of water. When water is kept in the pot 75% water get evaporated in 16 hrs. A suction mechanism attached in the pot sucks water at the rate which is also proportional to volume of water in the pot. Without evaporations, half of the water kept in pot is sucked in 24 hr The pot is filled with 16 kg of water, with evaporation and suction acting simultaneously , what amount of water (in kg) will be left is pot after one day.

Answer

`0001`

Explanation

Evaporations and reaction has rate similar to first order reaction rate hence
`1/t_(1//2)=1/((t_(1//2))_(evoparation))+1/((t_(1//2))_(suction))Rightarrow1/(t_(1//2))=6`hrs
`Hence water left =16/2^(4)=1kg`