Calculate the velocity with which the liquid gushes out of the `4cm^(2)` outlet, if the liquid flowing in the tube is water and liquid in `U` tube has a specific gravity `12`. Velocity of liquid at point `A` is `sqrt(20.2)m//s`

Options

A. `2.5 m//s`
B. `5.5 m//s`
C. `8 m//s`
D. `10 m//s`

Explanation

`P_(A)+(1)/(2)rhov_(A)^(2)=P_(B)+(1)/(2)rhov_(B)^(2)`
`P_(A)-P_(B)=(1)/(2)rho(v_(B)^(2)-v_(A)^(2))`
`0.02xx12000xx10=(1)/(2)xx1000(v_(B)^(2)-20.2)`
`4.8=v_(B)^(2)-20.2rArrv_(B)=5m//s`
`rArr A_(3).v_(B)=A_(1)v_(1)+A_(2)v_(2)`
`rArr 30=4v_(1)+8`
`rArr 4v_(1)=22rArrv_(1)=(22)/(4)=5.5m//s`