One mole of a diatomic gas undergoes a process `P = P_(0)//[1 + (V//V_(0)^(3))]` where `P_(0)` and `V_(0)` are constant. The translational kinetic energy of the gas when `V = V_(0)` is given by

Options

A. `(3P_(0)V_(0))/(2)`
B. `P_(0)V_(0)`
C. `(3P_(0)V_(0))/(4)`
D. `(5P_(0)V_(0))/(2)`

Explanation

`P=(P_(0))/(1+((V)/(V_(0)))^(3))=(P_(0))/(2)`
`T=(P_(0)V_(0))/(2R)`
`:. ` Translational kinetic energy is equal to `(3)/(2)RT=(3R)/(2)(P_(0)V_(0))/(2R)=(3P_(0)V_(0))/(4)`