The magnetic field at the centre of the circular loop as shown in Fig. when a single wire is bent to form a circular loop and also extends to form straight sections is

Options

A. `(mu_(0)I)/(2R)otimes`
B. `(mu_(0)I)/(2R)(1+(1)/(pisqrt(2)))odot`
C. `(mu_(0)I)/(2R)(1-(1)/(pisqrt(2)))odot`
D. `(mu_(0)I)/(2R)(1+(1)/(pisqrt(2)))otimes`

Explanation

`B_(AB)=(mu_(0)I)/(4piR)[sin90^(@)+sin(-45^(@))]ox`
`B_(BC)=(mu_(0)I)/(4piR)[sin90^(@)+sin45^(@)]o.`
`B_(0)=B_(AB)+B_(BC)+B_("circular")`