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A charged particle of mass `m` & charge `q` enters a zone of uniform magnetic field `B` with a velocity `v` making an angle `theta` with the boundary of the zone, having width `d`, when the particle penetrates half-way into the zone, the change in energy of the particel is

A

`(mv^(2))/(2B)sintheta`

B

`(Bqd)/(mv^(2))sintheta`

C

zero

D

`(mvd)/(qB)sintheta`

Text Solution

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As magnetic force is always perpendicular to velocity. No work is done by force.
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