In Young's doulbe-slit experiment the separation between two coherent sources `S_(1)` and `S_(2)` is d and the distance between the source and screen is D. In the interference pattern, it is found that exactly in front of one slit, there occurs a minimum. Then the possible wavelengths used in the experiment are

Options

A. `lambda=(d^(2))/(D)`, `(d^(2))/(3D)`, `(d^(2))/(5D)`……
B. `lambda=(d^(2))/(D)`, `(d^(2))/(5D)`, `(d^(2))/(9D)`……
C. `lambda=(d^(2))/(D)`, `(d^(2))/(2D)`, `(d^(2))/(3D)`……
D. `lambda=(d^(2))/(3D)`, `(d^(2))/(7D)`, `(d^(2))/(11D)`……

Explanation

Path difference`=d sintheta~~(d^(2))/(D)`