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The de Broglie wavelength of a thermal n...

The de Broglie wavelength of a thermal neutron at `927^circC` is `lamda`. Its wavelength at `327^circC` will be

A

`lambda//2`

B

`lambda//sqrt(2)`

C

`lambdasqrt(2)`

D

`2lambda`

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Use : `KE prop (momentum)^(2)`
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