A force `vecF=(3xy-5z)hatj+4zhatk` is applied on a particle. The work done by the force when the particle moves from point `(0, 0, 0)` to point `(2, 4, 0)` as shown in figure.

Options

A. `(280)/(5)`
B. `(140)/(5)`
C. `(232)/(5)`
D. `(192)/(5)`

Explanation

The `z`-component of the force and the `x`-component of displacement are ieffective here.
`dW=F_(y)dy=3xy.dy` (`:'z=0`)
`=6x^(4)dx` (`:'y=x^(2)` )
Integrating between `x=0` and `x=2` gives the result.