A block of mass `sqrt(3)//10kg` is placed on a rough horizontal surface as shown in the figure. A force of 1N is applied at one end of the block and the block remains stationary. The normal force exerted by the sruface on the block acts(g=10`m//s^(2)`)

Options

A. through the centre of mass of the block
B. through point `A`.
C. through point `B`.
D. through the point at a distance `5cm`. From `A`.

Explanation

For equilibrium
`sumvecF=0 sumvectau=0`
`N=(sqrt(3))/(2)-(1)/(2)`……..(`1`)
Torque about `A` due to all forces excluding normal face is found to be zero.