A circular conducting loop of radius `R` carries a current `I`. Another straight infinite conductor carrying current `I` passes through the diameter of this loop as shown in the figure. The magnitude of force exerted by the straight conductor on the loop is

Options

A. `pimu_(0)I^(2)`
B. `mu_(0)I^(2)`
C. `(mu_(0)I^(2))/(2pi)`
D. `(mu_(0)I^(2))/(pi)`

Explanation

`dF=((mu_(0)I)/(2piRsintheta)).(Ird theta)`
`rArr "Total force" F=intdF sin theta`
`=int_(0)^(2pi)(mu_(0)I^(2))/(2pi)d theta=mu_(0)I^(2)`