There are two identical square metallic plates kept on a rough horizontal floor at `t=0`, plates are given angular velocity `omega` and it is given that plate `1` is rotating about its centre `A` and plate `2` is rotating about one of its centre `O`. If `t_(1)` and `t_(2)` are the time taken by both the plates to come to rest then `(t_(1))/(t_(2))` is (Both are independent cases)

Options

A. `(1)/(2)`
B. `2`
C. `(1)/(4)`
D. `4`

Explanation

`tau alpha mgd`
`I.((dw)/(dt)) alpha mgd`
and `I=K.md^(2)`
Therefore `(dw)/(dt) alpha (1)/(d)`(Angular Acceleration of plate is independent of mass)
Now apply superposition principal