A gas, for which `gamma` is `(4)/(3)` is heated at constant pressure. The percentage of heat supplied used for external work is

Options

A. `12.5%`
B. `25%`
C. `35%`
D. `70%`

Explanation

`gamma=C_(p)//C_(v)=4//3`
Total heat supplied `dQ=nC_(p)dT`
Heat used up for work `dW=nRdT`.
`(dW)/(dQ)=(R )/(C_(p))=(C_(p)-C_(v))/(C_(p))=1-(C_(v))/(C_(p))`
`(dW)/(dQ)%=(1)/(4)xx100=25%`