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A parallel-plate capacitor has plate are...

A parallel-plate capacitor has plate area `A`, the distance between its two plates `x` and `y` is `d` and a dielectric slab of dielectric constant `epsilon_(r)` is filled between the regions. It is connected to a cell of emf `E`. If the dielectric slab is removed, then

A

`(epsilon_(0)A)/(d)[epsilon_(r)-1]E` charge is absorbed by the cell

B

`(epsilon_(0)A)/(d)[epsilon_(r)-1]E` charge flows through the circuit

C

negative charge flows from plate `y` to plate `x`

D

negative charge flows from plate `x` to plate `y`

Text Solution

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Since battery is connected. potential difference remains constant.
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