A particle of mass `1kg` is projected at an angle of `theta=pi//4` from horizontal with a muzzle velocity of `20 m//s`. A long slender rod of mass `5kg` and length `30 m` is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of `60m` from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (`g=10m//s^(2)`)
Angular velocity of rod after collision is

Options

A. `(1)/(4sqrt(2))rad//sec`
B. `(4)/(sqrt(2))rad//sec`
C. `4sqrt(2)rad//sec`
D. zero

Explanation

Hint : First find the point where collision occurs using equation of trajectory. Then use conservation of angular momentum. After collision energy conservation is valid.