A `10 kg` solid sphere of radius `r=0.8m` is rolling without slipping on a horizontal rough surface with `8 m//s`. The force applied by the right half of the sphere on the left half is `30x`. Newton. Find the value of `x`.

Explanation

`F=((10)/(2))(10^(2))xx(3xx0.8)/(8)`
`=5xx100xx0.3=150N`