A disc `'A'` of mass `M` is placed at rest on the smooth incline surface of inclination `theta`. A ball `B` of mass `m` is suspended vertically from the centre of the disc. A by a light inextersible string of length `l` as shown in the figure. If the acceleration of the disc `B` immediately after the system is released from rest is `((M+km)gsin^(2)theta)/(M+msin^(2)theta)`. Find `k`.

Explanation

`Mgsintheta+Tsintheta=Ma`
`mg-T=ma sintheta`
solving, we get
`a=((M+m)g sin^(2)theta)/(M+msin^(2)theta)`