Two particles `A` and `B` are situated at point `(60,0)` at `t=0`. The particle `A` move on a circle given by `X^(2)+Y^(2)=3600` and with a speed `6 pi m//s`, while `B` moves with a constant velocity.
(`a`) Find the velocity of `B` so that the collision takes places between `A` and `B` at point `(60,0)`.
(`b`) Calculate average acceleration of particle `A` during the motion.

Explanation

(`a`) Time for `A` to move from `(0,60)` to `(60,0)`
`=(2pixx60)/(4)xx(1)/(6pi)=5` second.
Displacement of `B=60hati-60hatj`
`:. ` Velocity of `B=(60hati-60hatj)//5=12(hati-hatj)m//s`

(`b`) `veca_("avg of A")=(Deltavecv)/(t)=(-6pihatj-6pihati)/(5)= -(6pi)/(5)[hati+hatj]m//s^(2)`