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A particle is moving along the path give...

A particle is moving along the path given by `y=(C )/(6)t^(6)` (where `C` is a positive constant). The relation between the acceleration (`a`) and the velocity (`v`) of the particle at `t=5sec` is

A

`5a=v`

B

`a=5v`

C

`a=sqrt(v)`

D

`a=v`

Text Solution

Verified by Experts

`y=(C )/(6)t^(6) rArr v=(dy)/(dt)=Ct^(5)`
`a=(dv)/(Dt)=5Ct^(4)`
`(a)/(v)=(5)/(t)`
So, at `t=5sec`, `(a)/(v)=1 rArr a=v`
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