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When a body is thrown up in a lift with ...

When a body is thrown up in a lift with a velocity `u` relative to the lift, the time of flight is found to be `t`. The acceleration with which the lift is moving up is

A

`(u-"gt")/(t)`

B

`(u+"gt")/(t)`

C

`(2u-"gt")/(t)`

D

`(u)/(t)-2g`

Text Solution

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`(2u)/(g+a)=t rArr a =(2u)/(t)-g`
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