Home
Class 11
PHYSICS
A particle of mass 3m is dropped from ce...

A particle of mass `3m` is dropped from certain height at `t=0` at time `t=t_(0)`. The particle explodes and breaks into two parts `m` and `2m`. At time `t=3t_(0)` velocity of lighter mass is `vecV=V_(1)hati+V_(2)hatj`. The velocity of heavier mass at `t=t_(0)` (just after explosion) is (if `y` represents vertical and `x` represents horizontal)

A

`-V_(1)hati-V_(2)hatj`

B

`-(V_(1))/(2)hati+((-V_(2)+5"gt"_(0)))/(2)hatj`

C

`-(V_(1))/(2)hati+((-V_(2)+5"gt"_(0))hatj)/(2)`

D

none of the above

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A particle of mass m is subjected to a force vecF=F_(0)[cos (t)hati+sin(1)hatj] . If initially (t=0) the particle was at rest, the kinetic energy of the particle as a function of time is given by:

A particle of mass m, moving in a circle of radius R, has a velocity v=v_(0)(1-e^(-gamma t)) The power delivered to tha particle by the force at t=0 is

If velocity v varies with time(t) as v=2t-3 , then the plot between v and t is best represented by :

A particle of mass m is moving with constant velocity v_(0) along the line y=b . At time t=0 it was at the point (0,b) . At time t=(b)/(v_(0)) , the

The velocity of a particle is v=v_(0)+g t+Ft^(2) . Its position is x=0 at t=0, then its displacement after time (t=1) is :

Power supplied to a particle of mass 2kg varies with time as P=3t^(2)/2 watt,where t is in seconds If velocity of particle at t=0 is v=0 the velocity of particle at t=2 sec will be ?

Power supplied to a particle of mass 4 kg varies with time as P=(3t^(2))/(2) watt. Here t in second. If velocity of particle at t = 0 is v = 0, the velocity of particle at time t = 2s will be

Power supplied to a particle of mass 3 kg varies with time as p = 4t ^(3) watt, where t in time is seconds. If velocity of particle at t =0s is u=2 m//s. The velocity of particle at time t =3s will be :

A time t = 0 , a body of mass 1 kg is dropped from height 500 m . At t = 1 sec , the body explodes into two parts of equal mass. One of them moves vertically upwards with velocity 5 m//s just after the explosion. The distance (in m ) between the parts at time t = 4 sec is 15x Then find x ?

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

FIITJEE-KINEMATICS-Example
  1. A fighter plane is flying horizontally at a height of 250m from ground...

    Text Solution

    |

  2. A ballon moves up vertically such that if a stone is thrown from it wi...

    Text Solution

    |

  3. A sailor in a boat, which is going due east with a speed of 8m//s obse...

    Text Solution

    |

  4. Two particles A and B are situated at point (60,0) at t=0. The particl...

    Text Solution

    |

  5. A block B is floating in the river. The position of the block is as sh...

    Text Solution

    |

  6. A driver applies the brakes on seeing traffic signal 400m ahead. At th...

    Text Solution

    |

  7. A particle is moving along the path given by y=(C )/(6)t^(6) (where C ...

    Text Solution

    |

  8. Which of the following statements can be possible cases in one//two di...

    Text Solution

    |

  9. A motor boat is to reach to a point 30^(@) upstream on other side of a...

    Text Solution

    |

  10. Choose the wrong statement from the following.

    Text Solution

    |

  11. The raindrops are hitting the back of a man walking at a speed of 5km/...

    Text Solution

    |

  12. A particle is thrown at time t = 0 with a velocity of 10 ms^(-1) at an...

    Text Solution

    |

  13. When a body is thrown up in a lift with a velocity u relative to the l...

    Text Solution

    |

  14. A particle of mass 3m is dropped from certain height at t=0 at time t=...

    Text Solution

    |

  15. A box is falling freely. Inside the box, a particle is projected with ...

    Text Solution

    |

  16. The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2)...

    Text Solution

    |

  17. The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2)...

    Text Solution

    |

  18. The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2)...

    Text Solution

    |