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An elastic ball of mass 'm' is suspended...

An elastic ball of mass `'m'` is suspended from a fixed point by an inextensible string. A small particle of same mass `m`, moving downwards at an angle of `37^(@)` with the vertical lits the ball directly with the velocity `v_(0)`. If the coefficient of restitution is `4//5`,
(`i`) find the velocity of the ball just after the impact.
(`ii`) determine the impulsive tension(i.e impulse) in the string at the instant of collision.

Text Solution

Verified by Experts

The particle after striking this ball will rebound with the velocity `v` exactly in the opposite direction.
Say `V` is the velocity attained by the ball after collision
Here the linear momentum remains conserved only in the horizontal direction.
`mv_(0)sin37^(@)+0=mV-mvsin37^(@)`
Along common normal, `e(v_(0)-0)=(Vsin37^(@)+v)`
`V=(37//34)v_(0)` and `v=(11//34)v_(0)`
Impulsive tension `=mv_(0)cos37^(@)+mvcos37^(@)`
`=mv_(0)(4)/(5)+m(11)/(34)v_(0)(4)/(5)=mv_(0)(18)/(17)`
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