When a car negotiates a curve, the normal force exerted on the inner and outer wheels are `N_(2)` and `N_(1)` respectively. Then `N_(1)//N_(2)` is

Options

A. `=1`
B. `lt 1`
C. `gt 1`
D. zero

Explanation

Referring to the free body diagram we obtain,
`sumF_(y)=N_(1)+N_(2)-mg=0`
`rArrN_(1)+N_(2)=mg`…..(`1`)
Along radial, `sumF_(r)=ma_(r)`
`rArrf_(r)=(mv^(2))/(r )`…..(`2`)
`sumtau_(G)=0`
`rArr N_(1)(d)/(2)+f_(r)h-N_(2)=(d)/(2)=0`…….(`3`)
Using `N_(2)-N_(1)=(2h)/(d)((mv^(2))/(r ))` and `N_(2)=mg//2+(h mv^(2))/(dr)rArr(N_(1))/(N_(2)) lt 1`.