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A particle is projected from the mid-poi...

A particle is projected from the mid-point of the line joining two fixed particles each of mass `m`. If the separation between the fixed particles is `l`, the minimum velocity of projection of the particle so as to escape is equal to

A

`sqrt((GM)/(l))`

B

`sqrt((GM)/(2l))`

C

`sqrt((2GM)/(l))`

D

`2sqrt((2GM)/(l))`

Text Solution

AI Generated Solution

To find the minimum velocity of projection of a particle so as to escape the gravitational influence of two fixed particles, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two fixed particles, each of mass \( m \), separated by a distance \( l \). - A third particle (also of mass \( m \)) is projected from the midpoint of the line joining the two fixed particles. ...
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