log(sec x+tan x)

int(sec x)/(ln(sec x+tan x))

int sec x ln(sec x+tan x)dx=

int sec x ln(sec x+tan x)dx=

((ln (sec x + tan x)) / (cos x) dx = ((ln (sec y + tan y)) / (cos y) dy

Let f(x)=(e^(tan x)-e^(x)+ln(sec x+tan x)-x)/(tan x-x) be a continuous function at x=0. The value f(0) equals

Let f (x)= (e ^(tan x) -e ^(x) +ln (sec x+ tan x)-x)/(tan x-x) be a continous function at x=0. The value of f (0) equals:

log (sec 2x +tan 2 x)

derivative of log (sec 2x +tan 2 x)

Differentiate the following w. r. t. x : log(sec 3x + tan 3x)