[" Problem "Pi1" A current of "4" ampere was passed for "1:5" hours through a solution of copper sulphate "],[" when "3*2" g of copper was deposited.Calculate the current efficiency."],[" Solution."]

A current of 4 amp was passed for 1.5 hours through a solution of copper sulphate when 3.2 g of copper was deposited. Calculate the current efficiency.

A current of 2A was passed for 1.5 hours through a solution of CuSO_(4) when 1.6g of copper was deposited. Calculate percentage current efficiency.

A current of 2A was passed for 1.5 hours through a solution of CuSO_(4) when 1.6g of copper was deposited. Calculate percentage current efficiency.

A current of 0.1A was passed for 4hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition. (Cu GAM 63.5 or Cu-63.5)

0.169 gram of copper is deposited on the cathode by a current of 32 milliamperes passing for 5 hours through a solution of copper sulphate. Determing the current efficiency. [ Atomic weight of Cu=63.6]