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An ellipsoidal cavity is carved within a...

An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Then

A

electrical field near `A` in the cavity must be equal to the eletric field near `B` in the cavity.

B

charge density at `A` must be equal to the charge density at `B`.

C

potential at `A` must be equal to the potential at `B`.

D

total electric field flux through the surface of the cavity is `q//epsilon_(0)`.

Text Solution

Verified by Experts

All the points which lies on the conductor are at the same potential. Again, according to Gauss's law, net flux through the surface of cavity `=(q)/(epsilon_(0))`
`:. (C )`, `(D)`
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