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Two identical sheets of a metallic foil ...

Two identical sheets of a metallic foil are separated by `d` and capacitance of the system is `C` and charged to a potential difference `E`. Keeping the charge constant, the separation is increased by `'l'`. Then, the new capacitance and potential difference will be

A

`(epsilon_(0)A)/(d)`, `E`

B

`(epsilon_(0)A)/(d+l)`, `E`

C

`(epsilon_(0)A)/(d+l)`, `(1+(l)/(d))E`

D

`(epsilon_(0)A)/(d)`, `(1+(l)/(d))E`

Text Solution

Verified by Experts

`q=CV=C_(1)V_(1)`
when `C = (epsilon_(0)A)/(d)` and
`q=(epsilon_(0)AE)/(d)=(epsilon_(0)AE_(1))/((d+l))`
`:. (epsilon_(0)A)/(d)E=(epsilon_(0)A)/((d+l))E_(1)`
`:. E_(1)=((d+l))/(d)*E`
`=(1+(l)/(d))*E`
and `C_(1)=(epsilon_(0)A)/(d+l)`
`:. (C )`
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