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When a galvanometer is shunted with a 4O...

When a galvanometer is shunted with a `4Omega` resistance the deflection is reduced to` 1//5`. If the galvanometer is further shunted with a `2Omega` wire the new deflection will be (assuming the main current remains the same)

A

`5//13` of the deflection when shunted with `4Omega` only

B

`8//13` of the deflection when shunted with `4Omega` only

C

`3//4` of the deflection when shunted with `4Omega` only

D

`3//13` of the deflection when shunted with `4Omega` only

Text Solution

Verified by Experts

When only `4Omega` resistance is shunted, `(i_(g))`, `=i//5`
`Gxxi//5=4xx(4i//5)rArrG=16Omega`

`(i_(g))_(2)=(4//3)/(16+4//3)i=(1)/(13)i`
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