Image of rod will just touch the rod only when one end of rod is at `'C'` center of curvature. So we have two options as illustrated in following figures.
If `'l'` be the length of image
In case `I`
`(1)/(V_(B))-(3)/((7f))=-(1)/(f)rArrV_(B)=-(7)/(4)f` & `l'=f|(7)/(4)-2|=f//4`
as `l' lt l` this is definitely not the case.
In case `II`
`(1)/(V_(B))-(3)/(5f)=-(1)/(f)`
`rArr V_(B)=-(5f)/(2)` and `l'=f|(5)/(@)-2|=(f)/(2)`
And the required linear magnification `=(l')/(l)=(3)/(2)`