Among the two interfering monochromatic sources A and B, A is ahead of B in phase by `66^@`. If the observation be taken from point P, such that `PB-PA=lambda//4`. Then the phase difference between the waves from A and B reaching P is
A
`156^(@)`
B
`140^(@)`
C
`136^(@)`
D
`126^(@)`
Text Solution
Verified by Experts
Total phase difference `=` initial phase difference `+` phase difference due to path `=66^(@)+(360^(@))/(lambda)xxDeltax` `=66^(@)+(360^(@))/(lambda)xx(lambda)/(4)=66^(@)+90^(@)=156^(@)`
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