`P` is small angled prism of angle `3^(@)` made of a material of refractive index `1.5`. A ray of light is incident normally to the mirror as shown in figure. `M` is a plane mirror. The angle of deviation for the ray reflected from the mirror `M` with respect to the incident ray is :
A
`4.5^(@)`
B
`175.3^(@)`
C
`177^(@)`
D
`178.5^(@)`
Text Solution
Verified by Experts
Total deviation `=(mu-1)A+(pi-2i)=178.5^(@)` `delta=i=(mu-1)A=1.5^(@)` where `i=` angle of incidence
FIITJEE|Exercise Numerical based questions|5 Videos
PHYSICS PART-III
FIITJEE|Exercise NUMERICAL BASED QUESTIONS DECIMAL TYPE|11 Videos
Similar Questions
Explore conceptually related problems
There is an equilateral prism of material of refractive index 1.5. Light ray is incident normally on its surface. What will be the angle of deviation of ray ?
A ray is incident at 30^(0) angle on plane mirror.What will be deviation after reflection from mirror ?
If a ray of light incident on a plane mirror is such that it makes an angle of 30^@ with the mirror, then the angle made by the reflected ray with the mirror is
When a ray of light is incident normally on a plane mirror then the angle of reflection will be
An incident ray strikes a plane mirror at an angle of 15^@ with the mirror. The angle between the incident ray and reflected ray is
A light ray is incident normally on a plane mirror. The angle of reflection will be
An incident ray strikes a plane mirror at an angle of 15^@ with the mirror. The angle between the reflected ray and the mirror is
A ray of light is incident at an angle of 35^@ on a plane mirror. What is the angle between the incident and the reflected rays ?
