In which of the following pairs `II^(nd)` compound has higher resonance energy:

Options

A. `CH_(2)=CH-OH&CH_(2)=CH-CH=CH-OH`
B.
C.
D. none of these

Explanation

To determine which of the given pairs of compounds has a higher resonance energy for the second compound, we will follow these steps:

### Step 1: Understand Resonance Energy
Resonance energy is the energy difference between the actual structure of a molecule and the most stable resonance structure. The more resonance structures a compound can have, the higher its resonance energy.

### Step 2: Analyze the Compounds
For each pair of compounds provided in the question, we need to analyze their structures to determine how many resonance structures can be drawn for each compound.

### Step 3: Identify Key Features
- Look for the presence of lone pairs, double bonds, and charges.
- Compounds with more delocalized electrons and fewer charges typically have higher resonance energy.

### Step 4: Compare the Resonance Structures
For each pair of compounds:
1. Draw the possible resonance structures for both compounds.
2. Count the number of significant resonance structures.
3. Evaluate the stability of these structures (considering factors like charge distribution and hybridization).

### Step 5: Determine the Higher Resonance Energy
After analyzing the resonance structures, determine which compound in each pair has a greater number of significant resonance structures and thus higher resonance energy.

### Conclusion
Based on the analysis, we can conclude which of the second compounds in the pairs has higher resonance energy.