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overset(H^(+))rarr(A)overset(H(2)O//H^(+...

`overset(H^(+))rarr(A)overset(H_(2)O//H^(+))rarrB+C`
Find A, B, C

Text Solution

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The correct Answer is:
`(##BSL_CHM_NC_E01_084_A01##)` `underset("Beckmann rearranged" )overset(H^(+))rarr` `CH_(3)-overset(O)overset(||)(C)-NH-CH_(2)-CH_(3)`overset(H_(2)//H^(+))to` `CH_(3)-COOH+CH_(3)-CH_(2)-NH(2)`
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