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The third term and nineth terms of an A....

The third term and nineth terms of an A.P. are 4 and -8 respectively. Find which term of A.P is equal to 0.

Text Solution

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Let `a` is the first term of `A.P.` and `d` is the common difference of the `A.P.`
Then, `a+2d = 4->(1)`
`a+8d = -8->(2)`
Subtracting (2)-(1),
`a+8d-a-2d = -8-4`
`d = -2`
Therefore, `a+2(-2) = 4 => a = 8`
Let `n` th term of this `A.P.` is `0`.
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