The surface density on a copper sphere is `sigma`. The electric field strength on the surface of the sphere is

The surface density on the copper sphere is 'sigma'. The electric field strength on the surface of the sphere is :

A spherical charged conductor has surface density of charge as sigma . The electric field intensity on its surface is E . If the radius of the surface is doubled, keeping sigma uncharged, what will be the electric field intensity on the new sphere ?

A spherical charged conductor has surface density of charge as sigma . The electric field intensity on its surface is E . If the radius of the surface is doubled, keeping sigma uncharged, what will be the electric field intensity on the new sphere ?

The electric field at a distance R due to charge q is E. If the same charge is placed on the copper sphere of radius R, the electric field strength at the surface of the conductor will be:

A spherical charged conductor has sigma as the surface density of charge. The electric field on its surface is E. If the radius of the sphere is doubled keeping the surface density of charge unchanged, what will be the electric field on the surface of the new sphere -

Charge density of the given surface is s. Then electric field stranght at the centre (of quarter sphere) is

A spherical charged conductor has sigma as the surface charge density. The electricfield on its surface is E. The radius of the sphere is doubled keeping the surface charge density unchanged. Then the electric field on the surface of the new sphere is,