" If "((3)/(2))^(-3)times((3)/(2))^(2x)=((3)/(2))^(5)," then "x=?

(2)/(2x-3)+(5)/((2x-3)^(2))=(3)/(3x-2)

Solve : ((3^(-2))^(2)times(5^(2))^(-3)times(p^(-3))^(2))/((3^(-2))^(5)times(5^(3))^(-2)times(p^(-4))^(3))

((2)/(3))^(4)times((3)/(2))^(5)times((5)/(3))^(-2)times((3)/(5))^(-3)

(3^(5x)xx81^(2)xx6561)/(3^(2x))=3^(7), then x=

Find the value of x in each of the following . (i) root5(5x + 2) = 2 (ii) root3(3x - 2) =4 (iii) ((3)/(4))^(3)((4)/(3))^(-7)= ((3)/(4))^(2x) (iv) 5^(x-3) xx 3^(2x -8) = 225 (v) (3^(3x) . 3^(2x))/(3^(x)) = root4(3^(20))

(5)/(x)x^(2)-(3)/(2)-(3)/(2)x^(2) =_____

(-(7)/(5)x^(2)y)xx((3)/(2)xy^(2))xx(-(6)/(5)x^(3)y^(3))

Simplify : (3x^(2))^(-3)xx(x^(9))^((2)/(3))