" (i) "(19(3)/(4))^(2)

If alpha and beta are the roots of the equation, [1,5][(1,3),(-4,7)]^(2)[(7/19, -13/19),(4/19,1/19)]^(4) [(1,3),(-4,7)]^(2)[(x^2 - 5x + 5),(-3)] = [-4] , then the value of (2 - alpha)(2 - beta) is

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (a) (19)/(64) (b) (64)/(19) (c) (27)/(16) (d) (-19)/(64)

(19^(@)-(-9)^(@))/(((-3)/(4))^(@))

Simplify and write the following in the exponential form: (i) ((-3)^(5)xx4^(6)xx4)/((-3)^(2)xx4^(9)) (ii) (11^(4)xx17^(3)xx19^(5))/(11^(2)xx17^(2)xx19^(2))

Let S=(4)/(19)+(44)/((19)^(2))+(444)/((19)^(3))+...oo then find the value of S

The value of tan(cos^(-1)(3/5)+tan^(-1)(1/4)) is (a) (19)/8 (b) 8/(19) (c) (19)/(12) (d) 3/4

Write the first negative term of the sequence 20, 19(1)/(4),18(1)/(2),17(3)/(4) …..