[" t for water is "1.86^(@)C" (m.Therefore.the freezing poin "],[" e "],[186^(@)C" (3) "-0.372^(@)C" 4) "+0.372^(@)C]

The molal freezing points constant of water is 1.86 K kg "mol"^(-1) . Therefore, the freezing point of 0.1 M NaCl in water is expected to be 1) -1.86^(@)C 2) -0.372^(@)C 3) -0.186^(@)C 4) +0.372^(@)C

The molal freezing point constant for water is 1.86^(@)C//m . Therefore, the freezing point of 0.1 M NaCl solution in water is expected to be:

The molal depression constant for water is 1.86^(@)C . The freezing point of a 0.05-molal solution of a non-electrolyte in water is