y=(sqrt(1-x^(2))(2x-3)^(1/2))/((x^(2)+2)^(2/3))

Expand each of the following (sqrt(2x)-3y)^(2)( ii) (2x-(1)/(3x))^(2)

If (sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2)))=3 then x=1)sqrt((2)/(3)2)sqrt((1)/(3))3)sqrt((2)/(5))sqrt((3)/(5))

Solution (1+x sqrt(x^(2)+y^(2)))dx+y(-1+sqrt(x^(2)+y^(2)))dy=0 is x-(y^(2))/(2)+(1)/(3)(x^(2)+y^(2))^((3)/(2))+c=0

Let tan^(-1)y=tan^(-1)x+tan^(-1)((2x)/(1-x^(2))) where |x|<(1)/(sqrt(3))* Then a value of y is : (1)(3x-x^(3))/(1-3x^(2))(2)(3x+x^(3))/(1-3x^(2))(3)(3x-x^(3))/(1+3x^(2))(4)(3x+x^(3))/(1+3x^(2))

The maximum value of y = sqrt((x-3)^(2)+(x^(2)-2)^(2))-sqrt(x^(2)-(x^(2)-1)^(2)) is

The maximum value of y = sqrt((x-3)^(2)+(x^(2)-2)^(2))-sqrt(x^(2)-(x^(2)-1)^(2)) is

The maximum value of y = sqrt((x-3)^(2)+(x^(2)-2)^(2))-sqrt(x^(2)-(x^(2)-1)^(2)) is

The maximum value of y = sqrt((x-3)^(2)+(x^(2)-2)^(2))-sqrt(x^(2)-(x^(2)-1)^(2)) is

y=sqrt(x^(2)-3x+2)+(1)/(sqrt(3+2x-x^(2))) find the domain =?