Two points charge `q_(1)` and `q_(2)(=q_(1)//2)` are placed at points `A(0,1)` and `B(1,0)` as shown in the figure.The electric field vector at point `P(1,1)` makes an angle `q` with the x-axis ,then the angle `q` is

Two point charge q_(1)=2muC and q_(2)=1muC are placed at distance b=1 and a=2cm from the origin on the y and x axes as shown in figure .The electric field vector at point (a,b) will subtend on angle theta with the "x-axis" given by

Two point charge q_(1)=2muC and q_(2)=1muC are placed at distance b=1 and a=2cm from the origin on the y and x axes as shown in figure .The electric field vector at point (a),(b) will subtnd on angle theta with the "x-axis" given by

Two point charge q_(1)=2muC and q_(2)=1muC are placed at distance b=1 and a=2cm from the origin on the y and x axes as shown in figure .The electric field vector at point (a),(b) will subtend on angle theta with the "x-axis" given by

Two point changes q_(1) = 2muC and q_(2) = 1muC are placed at distance b = 1cm and a = 2cm from the origin on the y and axes. The electric field vertor a point P (a.b) will subtend an angle .theta. with the x - axes given by

Two point charges q_(1) = 2 mu C and q_(2) = 1 mu C are placed at distances b = 1 cm and a = 2 cm from the origin on the Y and X axes as shown. The electric field vector at point P(a, b) will subtend an angle theta with X axis is given by

Charge 2q and -q are placed at (a,0) and (-a, 0) as shown in the figure. The coordinates of the point at which electric field intensity is zero will be (x,0) where

Charge 2q and -q are placed at (a,0) and (-a, 0) as shown in the figure. The coordinates of the point at which electric field intensity is zero will be (x,0) where