Three resistance `P, Q, R` each of `2 Omega` and an unknown resistance `S` from the four amrs of a Wheatstone's bridge circuit. When a resistance of `6 Omega` is connected in parallel to `S` the bridge gets balanced. What is the value of `S` ?

Three resistances P,Q,R each of 2 Omega and unknown resistance S form the four arms of a Wheatstone bridge circuit. When a resistance of 6 Omega is connected in parallel to S the bridge gets balanced.What is the value of S ?

Resistances P,Q,R,S of values 2,3,2,4 form a wheat stone bridge the resistance to be connected to S to have the bridge balanced is

With a resistance P Omega in the left gap and another resistance Q Omega in the right gap of a meter bridge, the balance point is obtained at 40 cm. When a resistance of 6 Omega is connected across Q, the balance point shifts to 50 cm. The value of resistance P is

Four resistances of 16 Omega , 12 Omega , 4 Omega and 9 Omega respectively are connected in cycle order so from a Wheatstone bridge. Calculate the resistance in be connected in parallel with 9 Omega resistance to balance the bridge.

The resistance of each arm of Wheatstone Bridge is 10 Omega . A resistance of 10 Omega is connected in series with the galvanometer then equivalent resistance across battery will be

A , B , C and D are four resistance of 2Omega , 2Omega , 2Omega and 3Omega respectivey. They are used to form a wheatstone bridge. The resistance D is short circuited with a resistance R in order to get the bridge balanced. The value of R will be